SOLUTION: The perimeter of a basketball court is 280 ft. The length is 44 ft longer than the width. Find the dimension of the court

Question 330078: The perimeter of a basketball court is 280 ft. The length is 44 ft longer than the width. Find the dimension of the court
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
The perimeter of a basketball court is 280 ft. The length is 44 ft longer than the width. Find the dimension of the court
.
Let L = length
and W = width
.
Then,
2(L+W) = 280 (equation 1)
L = W + 44 (equation 2)
.
Substitute the value of L from equation 2 into equation 1 to solve for W:
2(L+W) = 280
2(W+44+W) = 280
2(2W+44) = 280
2W+44 = 140
2W = 96
W = 48 feet (width)
.
Length:
W + 44 = 48 + 44 = 92 feet
.
Dimension: 48 by 92 feet
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