SOLUTION: Three squares are placed side-by-side to form a large rectangle The perimeter of the large rectangle is 64 centimeters. What is the area of one of the squares?

Question 327356: Three squares are placed side-by-side to form a large rectangle The perimeter of the large rectangle is 64 centimeters. What is the area of one of the squares?
Found 2 solutions by AAfter Search, ganeshindia:
Answer by AAfter Search(61) (Show Source): You can put this solution on YOUR website!
Let the side of the square be s cm
Length of the rectangle is 3s
Breadth of the rectangle is s
Perimeter of the rectangle is 2(Length + Breadth) = 2(3s + s) = 8s
Given, 8s = 64
=> s = 64/8 = 8
Hence, area of the square is 8 x 8 = 64 sq. cm.
Answer by ganeshindia(11) (Show Source): You can put this solution on YOUR website!
Let the side of the squares be l cm.
Then, the length of the rectangle = 3 times the side of a square
= 3l cm
The width of the rectangle = side of the square = l cm
Given that, Perimeter of the rectangle = 64 cm.
2 (length + width) = 64
2 (3l + l) = 64
2(4l) = 64
8l = 64
l = 64/8
l = 8 cm
side of the one of squares = 8 cm
Therefore the area of one of the squares = 8 X 8 = 64 sq.cm
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