SOLUTION: the Length of a rectangle is four times its width. If the area of the rectangle is 324 yd^2, find its perimeter
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Question 323889: the Length of a rectangle is four times its width. If the area of the rectangle is 324 yd^2, find its perimeter
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
Length = 4x
Width = x
Area = 324
324 = (4x)(x)
324 = 4x^2
324/4 = x^2
81 = x^2
sqrt[81] = sqrt[x^2]
9 = x
We find the perimter using P = 2L + 2W.
P = 2(4x) + 2(x)
P = 2(4*9) + 2(9)
P = 2(36) + 18
P = 72 + 18
P = 90 yards
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