SOLUTION: I know the formula for a rectangle P=2L+2W and A=LH, but what if the area and P are given? here is my question. Is it possible to have a rectangle with an area of 24 square met

Question 31402: I know the formula for a rectangle P=2L+2W and A=LH, but what if the
area and P are given? here is my question.
Is it possible to have a rectangle with an area of 24 square meters and a
perimeter of 96 meters? Give proof.
How do I use the formulas for this problem? Help.
Zack
Answer by Paul(988) (Show Source): You can put this solution on YOUR website!
To see if this happens, lew x be the length and let y be the width:
2(x+y)=96
y=48-x (subsitution:)
AreA:
xy=24
Subsitute for y:
x(48-x)=24
48x-x^2=24
-x^2+48x-24=0
x^2-48x+24=0
Use the quadratic formula:

--> REMOVE NEGATIVE SIGN

x=47
y=1
47*1=47
So it is not possible.
Paul.
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