# SOLUTION: the perimeter of a rectangle is 80 m. the length is 1 m more than twice the width. find the dimensions. what is the length? what is the width?

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Question 313116: the perimeter of a rectangle is 80 m. the length is 1 m more than twice the width. find the dimensions. what is the length? what is the width?
Found 2 solutions by ichudov, stanbon:
You can put this solution on YOUR website!
two sides are L and W.
perimeter is 2L+2W = 80.
L=1+2W
2(1+2W)+2W=80
Solved by pluggable solver: EXPLAIN simplification of an expression

 Here's what you tried: This is an equation! Solutions: W=13. Graphical form: Equation was fully solved.Text form: 2*(1+2W)+2W=80 simplifies to 0=0Cartoon (animation) form: For tutors: `simplify_cartoon( 2*(1+2W)+2W=80 )` If you have a website, here's a link to this solution.

### DETAILED EXPLANATION

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Expanded term by using associative property on
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Multiplied numerator integers
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Eliminated similar terms , replacing them with
It becomes .

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Remove unneeded parentheses around factor
It becomes .

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Solved linear equation equivalent to 6*W-78 =0
It becomes .
Result:
This is an equation! Solutions: W=13.

### Universal Simplifier and Solver

Done!

W=13
L=1+2W=1+2*13=27

You can put this solution on YOUR website!
the perimeter of a rectangle is 80 m. the length is 1 m more than twice the width. find the dimensions. what is the length? what is the width?
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P = 2(L + W)
----
80 = 2((2W+1)+W)
40 = 3W+1
3W = 39
W = 13 m (width)
L = 2W+1 = 27 m (length)
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Cheers,
Stan H.
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