SOLUTION: The length of a rectangle is twice the width; the perimeter is 42 inches. Find the width?

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Question 308338: The length of a rectangle is twice the width; the perimeter is 42 inches. Find the width?
Answer by ichudov(507)   (Show Source): You can put this solution on YOUR website!
Let's use "w" for width.
Then length is 2w.
The perimeter is two lengths, plus two widths:
perimeter = 42 = 2*2w+2*w
Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: w=7.
  • Graphical form: Equation was fully solved.
  • Text form: 42=2*2w+2*w simplifies to 0=0
  • Cartoon (animation) form:
    For tutors: simplify_cartoon( 42=2*2w+2*w )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION


Look at .
Multiplied numerator integers
It becomes .

Look at .
Eliminated similar terms highlight_red%28+4%2Aw+%29,highlight_red%28+2%2Aw+%29 replacing them with highlight_green%28+%284%2B2%29%2Aw+%29
It becomes .

Look at .
Added fractions or integers together
It becomes .

Look at .
Remove unneeded parentheses around factor highlight_red%28+6+%29
It becomes .

Look at .
Moved these terms to the left highlight_green%28+-6%2Aw+%29
It becomes .

Look at .
Moved 42 to the right of expression
It becomes .

Look at .
Solved linear equation highlight_red%28+-6%2Aw%2B42=0+%29 equivalent to -6*w+42 =0
It becomes .
Result:
This is an equation! Solutions: w=7.

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