SOLUTION: The area of a rectangle is 21sqft. What are the dimensions is the length is 5 less four times the width.

Algebra.Com
Question 303318: The area of a rectangle is 21sqft. What are the dimensions is the length is 5 less four times the width.
Found 2 solutions by nyc_function, user_dude2008:
Answer by nyc_function(2741)   (Show Source): You can put this solution on YOUR website!
Here is your equation and you can then solve the problem.
21 = (4x - 5)(x)

Answer by user_dude2008(1862)   (Show Source): You can put this solution on YOUR website!
21=LW
L=4W-5

21=(4W-5)W

4W^2-5W-21=0

(W-3)(4W+7)=0

W-3=0 or 4W+7=0

W=3 or W=-7/4 Ignore

Answer: Width = 3, length = 7

RELATED QUESTIONS

What are the dimensions of a rectangle if the length is 5 less than three times the width (answered by Alan3354)
What are the dimensions of a rectangle if the length is 5 less than three times the width (answered by richard1234)
the length of a rectangle is 1m less than four times the width. if the area of the... (answered by ReadingBoosters)
The length of a rectangle is 7 centimeters less than four times its width. Its area is 15 (answered by JBarnum)
The length of a rectangle is four less than three times the width. The area is 20 square... (answered by checkley75)
the length is the rectangle is 7ft less than four times its width. If the area is 36ft^2, (answered by CubeyThePenguin)
The length of a rectangle is five less than four times the width. If the area is 9ft^2,... (answered by josgarithmetic)
The perimeter of a rectangle is 900 meters. The length is fifteen less than four times... (answered by Fombitz)
The length of a rectangle is 13 centimeters less than four times its width. Its area is... (answered by addingup,MathTherapy)