SOLUTION: 66 feet around a rectangle. The width is 3 more feet than the length
Find the width and length
Algebra.Com
Question 302784: 66 feet around a rectangle. The width is 3 more feet than the length
Find the width and length
Answer by JBarnum(2146) (Show Source): You can put this solution on YOUR website!
66=P
P=2L+2W
W=(3+L)
distribute the 2
add like terms and subtract 6 from both sides
divide by 4
RELATED QUESTIONS
The width of a rectangle is 3 feet more than twice the length. If the perimeter is 60... (answered by checkley79)
The length of a rectangle is 6 feet less than twice the width. The perimeter is 66 feet.... (answered by checkley77)
the length of a rectangle is 6 ft longer than twice the width. if the perimeter is 66... (answered by FrankM)
The length of a rectangle is 2 feet more than 3 times the width. If the area is 16 square (answered by mathsmiles)
The length of a rectangle is 3 feet more than 4 times the width. If the area is 45... (answered by Cromlix)
The length of a rectangle is 4 feet more than 3 times the width. If the area is 64 square (answered by ewatrrr)
the length of a rectangle is 7 feet more than width. if the length were decreased by 3... (answered by solver91311)
The length of a rectangle is 3 more than the width. The area is 88 square feet. Find the... (answered by Fombitz)
the length of a rectangle is 3 feet less than five times its width. the perimeter is 66... (answered by ptaylor)