# SOLUTION: I have presented this problem in the past and have not gotten a clear understanding of what is the correct formula and steps to take to get the correct answer. Please Help!!! Th

Algebra ->  Rectangles -> SOLUTION: I have presented this problem in the past and have not gotten a clear understanding of what is the correct formula and steps to take to get the correct answer. Please Help!!! Th      Log On

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 Geometry: Rectangles Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Rectangles Question 302686: I have presented this problem in the past and have not gotten a clear understanding of what is the correct formula and steps to take to get the correct answer. Please Help!!! Ther perimeter of a rectangle is 20 meters. If the length is increased by four times the width, the sum is 19 meters. What are the dimensions of the rectangle? What is its area?Found 2 solutions by Fombitz, ankor@dixie-net.com:Answer by Fombitz(13828)   (Show Source): You can put this solution on YOUR website!Let's put down some formula first. . . . Now let's use the information we have, "The perimeter of a rectangle is 20 meters" 1. "If the length is increased by four times the width, the sum is 19 meters" 2. Now you have 2 equations with 2 unknowns. Use eq. 1, Now substitute into eq. 2, Then from eq. 1, Then from those two, Answer by ankor@dixie-net.com(16524)   (Show Source): You can put this solution on YOUR website!The perimeter of a rectangle is 20 meters. If the length is increased by four times the width, the sum is 19 meters. What are the dimensions of the rectangle? What is its area? : Let L = the length of the rectangle Let W = the width : Write an equation for each statement "The perimeter of a rectangle is 20 meters." 2L + 2W = 20 We can simplify this divide by 2, results: L + W = 10 W = (10-L); this form for substitution : "the length is increased by four times the width, the sum is 19 meters." L + 4W = 19 Substitute W with (10-L) L + 4(10-L) = 19 L + 40 - 4L = 19 L - 4L = 19 - 40 -3L = - 21 L = L = +7m is the length : What are the dimensions of the rectangle? find the width W = 10 - L W = 10 - 7 W = 3m : Dimensions: 7 by 3 : What is its area? 7 * 3 = 21 sq/m : : Check solutions by finding the perimeter with these dimensions 2(7) + 2(3) = 20