SOLUTION: The length of a rectangle is increased by 15% and the width is decreased by 20%. Compared to the area of the original rectangle,the area of the new rectangle is (a) 8% less (b

Question 288284: The length of a rectangle is increased by 15% and the width is decreased by
20%. Compared to the area of the original rectangle,the area of the new
rectangle is
(a) 8% less (b) 5% less (c) the same (d) 5% more (e) l2% more
Answer by amnd(23) (Show Source): You can put this solution on YOUR website!
Of course, the area of the original rectangle would be L (length) x W (width) = LW
The new rectangle has a length 15% more than the original, which means that its length is 100 + 15 = 115% of the original rectangle, or 1.15L.
The new rectangle has a width 20% less than the original, which means that its width is 100 - 20 = 80% of the original rectangle, or 0.8W.
To gain the value of the new area, we only need to multiply the new length and width, yielding:
1.15*0.8*LW = 0.92LW
This is 92/100, or 92% of the original rectangle's area. 92% is 8% away from 100%, which means that the new rectangle's area is 8 % less (a) than the original.
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