SOLUTION: 1.area of a rectangle is 33 square inches. If the length is 2 more than three times the width, find the length and the width.

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Question 286216: 1.area of a rectangle is 33 square inches. If the length is 2 more than three times the width, find the length and the width.
Answer by mestrydilip(13)   (Show Source): You can put this solution on YOUR website!
Area = 33 Sq.inches.
Let us assume width to be x inches.
Length = (3x + 2)
x (3x + 2) = 33 Area of Rectangle = Length X Width
3x^2 + 2x = 33
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=400 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 3, -3.66666666666667. Here's your graph:


Hence if x = 3
Length = 11 inches
Width = 3 inches
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