SOLUTION: The perimeter of a rectangle is to be no greater than 300 in., and the length must be 125 in. Write an appropriate inequality, then find the maximum width of the rectangle. 300

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Question 28442: The perimeter of a rectangle is to be no greater than 300 in., and the length must be 125 in. Write an appropriate inequality, then find the maximum width of the rectangle.
300>250+2W
I'm lost am I doing this right.

Found 2 solutions by elima, josmiceli:
Answer by elima(1433)   (Show Source): You can put this solution on YOUR website!
Yes your doing a great job! Now is all you need to do is find w.
300>250+2w
subtract 250 from both sides;
300-250>2w
50>2w
Now divide each side by 2;
>
25>w
=)

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
It's almost right
"no greater than" is another way of saying "less than or equal to"
the perimeter = 2l + 2w
2l + 2w <= 300
w = 125
2l + 2(125) <= 300
2l + 250 <= 300 (this is close to what you got)
subtract 250 from both sides
2l <= 50
l <= 25

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