# SOLUTION: a rectangles lengeth is five inches less than four times its width. if the perimeter is fourty inches what are the dimensions of the rectangle

Algebra ->  Algebra  -> Rectangles -> SOLUTION: a rectangles lengeth is five inches less than four times its width. if the perimeter is fourty inches what are the dimensions of the rectangle       Log On

 Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Geometry: Rectangles Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Rectangles Question 282715: a rectangles lengeth is five inches less than four times its width. if the perimeter is fourty inches what are the dimensions of the rectangle Found 2 solutions by oberobic, unlockmath:Answer by oberobic(2304)   (Show Source): You can put this solution on YOUR website!L = length W = width P = 2L + 2W = perimeter . P = 40 :: given . L = 4W -5 :: length is 5 less than 4*Width . Substitute and solve for W. . 2L + 2W = P 2(4W-5) + 2W= 40 8W -10 + 2W = 40 10W -10 = 40 10W = 50 W = 5 . L = 4W-5 L = 4(5) -5 L = 20 - 5 L = 15 . Checking the perimeter will tell if this is the right answer 2L + 2W = 40?? . 2(15) = 30 2(5) = 10 30+10 = 40 Correct. . Answer: The dimensions of the rectangle are length = 15 and width = 5. . Done. Answer by unlockmath(1599)   (Show Source): You can put this solution on YOUR website!Hello, Let the width be x and the length will be 4x-5. Now we can set up our equation as: x+x+(4x-5)+(4x-5)=40 Combine like terms to get: 10x-10=40 Add 10 to both sides and divide by 10 to get: x=5 There we go the width is 5 inches. I'll let you figure out the width. (Note: Lenegth is spelled length and fourty is spelled forty) RJ Check out a book I wrote: www.math-unlock.com