SOLUTION: The width of a rectangle is 6 inches less than one-half the length. Find the length and the width of the rectangle if the perimeter of the rectangle is 72 inches.

Question 280802: The width of a rectangle is 6 inches less than one-half the length. Find the length and the width of the rectangle if the perimeter of the rectangle is 72 inches.
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
w = width
l = length
w = 1/2*l - 6
P = 2(l+w) = 72
2l + 2w = 72
.
substitute w = 1/2*l -6
.
2l + 2w= 72
2l + 2(1/2*l - 6) = 72
2l + l - 12 = 72
3l = 84
l= 28
.
w = 1/2*l -6 = 1/2*28 - 6 = 14-6 = 8
.
checking
2l + 2w = 72?
2l = 2*28 = 56
2w = 2*8 = 16
56+16= 72
Correct.
.
Answer:
length = 28
width = 8
.
Done
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