SOLUTION: a rectangle has an area that is numerically twice its perimeter. if the length is twice the width, what are the dimensions?
Algebra ->
Rectangles
-> SOLUTION: a rectangle has an area that is numerically twice its perimeter. if the length is twice the width, what are the dimensions?
Log On
You can put this solution on YOUR website! a rectangle has an area that is numerically twice its perimeter.
:
L*W = 2(2L+2W)
:
If the length is twice the width, what are the dimensions?
:
Replace L with 2W
(2W)*W = 2[2(2W) + 2W)]
2W^2 = 2(4W + 2W)
2W^2 = 2(6W)
;
divide both sides by 2
W^2 = 6W
W^2 - 6W = 0
:
factor out W
W(W - 6) = 0
:
Two solutions
W = 0, meaningless
and
W = 6 units is the width
then
2(6) = 12 units is the length
:
:
Is this true?
12*6 = 2(2(12) + 2(6))
72 = 2(24 + 12),
