SOLUTION: the permitere of a rectangle is 52 feet. the length and width are represented by two consecutive even intetgers. find the dimensions of the rectangle

Algebra.Com
Question 264083: the permitere of a rectangle is 52 feet. the length and width are represented by two consecutive even intetgers. find the dimensions of the rectangle

Answer by Greenfinch(383)   (Show Source): You can put this solution on YOUR website!
Length and width = 1/2 x 52 = 26
If consecutive, halve 26 to get 13, then add one and subtract one to get 12 and 14

RELATED QUESTIONS

The Perimeter of a rectangle is 52 feet. The length and width are represented by two... (answered by checkley77)
The perimeter of a rectangle is 52 feet. The length and width are represented by two... (answered by Fombitz)
how do you find the dimensions of a rectangle if the perimeter is 52 feet and the length... (answered by checkley77)
The width, length, and diagonal of a rectangle are consecutive even integers. Find the... (answered by checkley77)
the length of a rectangle is represented by x+7 and the width is represented by x+1. If... (answered by mananth)
The length and width of a rectangle are consecutive even integers. The perimeter is 44... (answered by tommyt3rd)
The length and width of a rectangle are consecutive even integers. The perimeter is 92... (answered by josgarithmetic)
If the area of a rectangle is represented by x^2+8x+15 and its length is represented by... (answered by Alan3354)
The length and width of a rectangle are represented as consecutive integers, the... (answered by user_dude2008,solver91311)