SOLUTION: The perimeter of a rectangle is 100 meters. Its length is 7 meters less than twice its width. Find its area.

Question 261632: The perimeter of a rectangle is 100 meters. Its length is 7 meters less than twice its width. Find its area.
Found 2 solutions by mananth, MathTherapy:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangle is 100 meters. Its length is 7 meters less than twice its width. Find its area
Let the width be x
Twice width = 2x
Seven less than twice the width = 2x-7
Perimeter = 2*(l+w)
= 2*(2x-7+x)
= 2*(3x-7)
= 6x-14 =100
2x= 114
X= 57
Width =2x = 114
Area = L*w= 114 * 57=6498 square meters
M Ananth------------ mananth@hotmail.com

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangle is 100 meters. Its length is 7 meters less than twice its width. Find its area.

Let width be W

Then length = 2W - 7, since its length is 7 meters less than twice its width

Since its perimeter is 100 meters, and since perimeter = 2W + 2L, we will then have:

2W + 2(2W - 7) = 100

2W + 4W - 14 = 100

6W = 114

W, or width = meters

Since its width, or W = 19, then L, or its length = 31 (2*19 - 7)

Since its width = 19, and length = 31, then its area = 19 * 31 = , or squared meters.
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