SOLUTION: a rectangle whose perimeter is 176 feet, has a length that is six feet longer than its width. what is the area of the rectangle?
Algebra.Com
Question 261044: a rectangle whose perimeter is 176 feet, has a length that is six feet longer than its width. what is the area of the rectangle?
Answer by Greenfinch(383) (Show Source): You can put this solution on YOUR website!
Let width be W, then length is W + 6
Perimeter is 2(W + W + 6) = 176
2W + 6 = 88
2W = 82
W = 41, length = 47 feet
Area is 41 x 47 = 1927 sq feet
RELATED QUESTIONS
A rectangle has a length that is 3 feet longer than is width. Its perimeter is 26 feet.... (answered by pmesler)
A rectangle with a perimeter of 98 feet has a length 31 feet longer than its width. What (answered by josgarithmetic)
The length of a rectangle is 6 feet longer than its width. The perimeter is 44 feet. what (answered by ewatrrr)
The area of a rectangle is 36 square feet. Find the length and the width of the rectangle (answered by ikleyn)
The length of a rectangle is three feet longer than six times its width.
If the area of... (answered by macston)
the length of a rectangle is 5 feet longer than its width. If its area is 36 square feet, (answered by TimothyLamb)
A rectangle has a length that is 6 feet more than the width. Its perimeter is 100 feet.... (answered by hamsanash1981@gmail.com)
A rectangle has a length that is 6 feet more than the width. Its perimeter is 100 feet.... (answered by ewatrrr)
Find the dimensions of a rectangle whose length is a foot longer than twice its width and (answered by richwmiller)