SOLUTION: The length of a rectangle is 2 ft more than four times the width. Express as an interger the maximum width of the rectangle when the perimeter is less than 34 ft ?

Question 257815: The length of a rectangle is 2 ft more than four times the width. Express as an interger the maximum width of the rectangle when the perimeter is less than 34 ft ?
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
Let length = L and width = W.
from the given information, we get
L = 4W + 2
P = 2L + 2W
34 > 2(4W+2) + 2W
34 > 10W + 4
30 > 10W
3 > W
The maximum width is 2.
If W = 2
L = 10
P = 24 < 34
--
If W = 3
L = 14
P = 34 this is NOT LESS than 34.
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