SOLUTION: the perimeter of a rectangle is 70 inches the length exceeds the width by 19 inches. Find the length and the width.
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Question 254481: the perimeter of a rectangle is 70 inches the length exceeds the width by 19 inches. Find the length and the width.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
L=W+19
2L+2W=70
2(W+19)+2W=70
2W+38+2W=70
4W=70-38
4W=32
W=32/4
W=8 ANS. FOR THE WIDTH.
L=8+19=27 ANS. FOR THE LENGTH.
PROOF:
2*27+2*8=70
54+16=70
70=70
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