# SOLUTION: If the diagonal of a rectangle has length 7 feet and the rectangle’s area is 16 square feet, what is the perimeter of the rectangle in feet? a 10 feet b 15 feet c 18 feet d 2

Algebra ->  Algebra  -> Rectangles -> SOLUTION: If the diagonal of a rectangle has length 7 feet and the rectangle’s area is 16 square feet, what is the perimeter of the rectangle in feet? a 10 feet b 15 feet c 18 feet d 2      Log On

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 Click here to see ALL problems on Rectangles Question 252288: If the diagonal of a rectangle has length 7 feet and the rectangle’s area is 16 square feet, what is the perimeter of the rectangle in feet? a 10 feet b 15 feet c 18 feet d 23 feet e 26 feet Answer by checkley77(12569)   (Show Source): You can put this solution on YOUR website!FOR THE AREA OF THE RECTANGLE: XY=16 OR X=16/Y FOR THE TRIANGLE: X^2+Y^2=7^2 (16/Y)^2+Y^2=49 (256/Y^2)+Y^2=49 (256+Y^4)/Y^2=49 256+Y^4=49Y^2 Y^4-49Y^2+256=0 Y^2=(49+-SQRT[-49^2-4*1*256])/2*1 Y^2=(49+-SQRT[2,401-1.024])/2 Y^2=(49+-SQRT1,377)/2 Y^2=(49+-37.108)/2 Y^2=(49+37.108)/2 Y^2=86.108/2 Y^2=43.05 Y=SQRT43.05 Y=6.56 ANS. THEN X=2.44 Y^2=(49-37.108)/2 Y^2=11.892/2 Y^2=5.95 Y=SQRT5.95 Y=2.44 ANS. THEN X=6.56 PROOFS: 6.56*2.44=16 16~16 6.56^2+2.44^2=49 43.03+5.954=49 49~49 tHUS THE PERIMETERIS: 2*6.56+2*2.44=13.12+4.88=18 FT. IS THE PERIMETER. ANSWER C)