SOLUTION: please guide me on how to solve this problem:
the length of a rectangle is 5cm. more than twice the width. the perimeter of the rectangle is 34 cm. find the dimensions of the rec
Algebra.Com
Question 249465: please guide me on how to solve this problem:
the length of a rectangle is 5cm. more than twice the width. the perimeter of the rectangle is 34 cm. find the dimensions of the rectangle.
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
Turn each statement into an equation using the fewest possible unknowns.
.
L = length of the rectangle
.
Length is twice the width plus 5.
L = 2W + 5
.
P = perimeter of a rectangle.
P = 2L + 2W = 2(L + W)
P = 34 (given)
.
Substituting what we know...
34 = 2(L + W)
.
Divide both sides by 2...
17 = L + W
.
Substituting L = 2W+5...
17 = 2W + 5 + W
.
Collecting terms and subtracting 5 from both sides
12 = 3W
so
3W = 12
.
Dividing both sides by 3
W = 4
.
L = 2W+5
L = 2(4)+5
L = 8+5
L = 13
.
Checking the perimeter
P = 2(L+W) = 2(13+4) = 2(17) = 34
.
Checks.
RELATED QUESTIONS
please help me solve this problem: the length of a rectangle is 4cm more than twice its... (answered by stanbon)
Could someone please show me how to solve this problem?
The perimeter of a rectangle is... (answered by Gogonati)
Can you show me how to solve this problem using algebra? The length of the rectangle is 3 (answered by Paul)
find the perimeter of a rectangle whose length is 5cm less than twice its... (answered by mananth)
Please help me solve this word problem. Three times the width of a certain rectangle... (answered by ankor@dixie-net.com)
Hello, I would like a good explanation on how to solve this word problem, I am not very... (answered by stanbon,rfer)
If the area of this rectangle is 105cm2 then the length is ____cm, the width is ____ cm,... (answered by Earlsdon)
I would like help on how to solve this story problem: The length of a rectangle is 9ft... (answered by josgarithmetic)
Please help me with this problem :
Write an expression for the perimeter of a... (answered by ewatrrr)