SOLUTION: The length of a rectangle is twice its width. If the perimeter of the rectangle is 48 yd , find its area.
Algebra.Com
Question 249430: The length of a rectangle is twice its width. If the perimeter of the rectangle is 48 yd , find its area.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
L=2W
2L+2W=P
2(2W)+2W=48
4W+2W=48
6W=48
W=48/6
W=8 YDS. FOR THE WIDTH.
L=2*8=16 YDS. FOR THE LENGTH.
PROOF:
2*16+2*8=48
32+16=48
48=48
RELATED QUESTIONS
The length of a rectangle is three times its width.
If the perimeter of the rectangle... (answered by Cromlix)
The length of a rectangle is 6 yd longer than its width.
If the perimeter of the... (answered by CharlesG2)
The length of a rectangle is 3 yd longer than its width.
If the perimeter of the... (answered by rapaljer)
The length of a rectangle is
2
yd
longer than its width.
If the perimeter of... (answered by IBMath)
The length of a rectangle is
5 yd longer than its width.
If the perimeter of the... (answered by Alan3354)
The length of a rectangle is
3
yd
longer than its width.
If the perimeter of... (answered by Alan3354)
The length of a rectangle is 5 yd longer than its width.
If the perimeter of the... (answered by ankor@dixie-net.com)
The length of a rectangle is 4yd longer than its width. If the perineter of the rectangle (answered by JulietG)
The length of a rectangle is 1 yd more than twice its width, and the area of the... (answered by checkley77)