SOLUTION: the perimeter of a rectangle is 56 cm. The width is 6 cm less than the length. Find the width and the length.

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Question 246659: the perimeter of a rectangle is 56 cm. The width is 6 cm less than the length. Find the width and the length.
Answer by rapaljer(4671)   (Show Source): You can put this solution on YOUR website!
Let x= length (because this is the last phrase in the first sentence!)
x-6 = width

2W + 2L = Perimeter
2(x-6) +2(x)= 56
2x-12+2x=56
4x-12=56

Add +12 to each side:
4x-12+12=56+12
4x=68
x=17 Length
x-6=11 Width

Check:
2*17+2*11
34+22
56 It checks!!

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