SOLUTION: the length of a rectangle is twice its width the area of the rectangle is 648 what are the dimensions (length and width) of the rectangle? what is the perimeter?

Question 245631: the length of a rectangle is twice its width the area of the rectangle is 648 what are the dimensions (length and width) of the rectangle? what is the perimeter?
Found 2 solutions by TheProdicalSon, checkley77:
Answer by TheProdicalSon(34) (Show Source): You can put this solution on YOUR website!
n = length
w = width
2w = n
2w * w = 648
2w + w^2 = 648
-2w -2w
w^2 = 648-2w
*2 *2
2w^2 = 1296 - 4w
Square both sides
solve
w = 18
n = 36
P = 2n + 2w
P = 108

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
L=2W
AREA=LW
648=LW
648=2W*W
648=2W^2
W^2=648/2
W^2=324
W=SQRT324
W=18 ANS. FOR THE WIDTH.
L=2*18=36 ANS. FOR THE LENGTH.
PROOF:
18*36=648
648=648
P=2L+2W
P=2*18+2*36
P=36+72
P=108 ANS. FOR THE PERIMETER.
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