SOLUTION: there is a similar question on here but it doesnt show how to solve it. The perimeter of a rectangle yard is 270 feet. If its length is 25 feet greater than its width what are th

Algebra ->  Algebra  -> Rectangles -> SOLUTION: there is a similar question on here but it doesnt show how to solve it. The perimeter of a rectangle yard is 270 feet. If its length is 25 feet greater than its width what are th      Log On

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 Click here to see ALL problems on Rectangles Question 235396: there is a similar question on here but it doesnt show how to solve it. The perimeter of a rectangle yard is 270 feet. If its length is 25 feet greater than its width what are the dimensions of the yard?Answer by checkley77(12569)   (Show Source): You can put this solution on YOUR website!L=W+25 2L+2W=270 2(W+25)+2W=270 2W+50+2W=270 4W=270-50 4W=220 W=220/4 W=55 THE WIDTH. L=55+25=80 THE LENGTH. PROOF: 2*80+2^55=270 160+110=270 270=270