SOLUTION: The perimeter of a rectangle is 54 feet and its area is 180 square feet. What are the dimensions of the rectangle?
Algebra.Com
Question 232748: The perimeter of a rectangle is 54 feet and its area is 180 square feet. What are the dimensions of the rectangle?
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
a) 2(L+w)=54
b) Lw=180
.
a)
2L+2w=54
2L=54-2w
L=27-w
b)
w(27-w)=180
27w-w^2=180
w^2-27w+180=0
(w-12)(w-15)=0
w=12', L=15'
.
Ed
RELATED QUESTIONS
The area of a rectangular piece of concrete is 120 square feet, and its perimeter is 46... (answered by minerva,arunpaul)
The width of a rectangle is 18 feet less than the perimeter. the area of the rectangle is (answered by lynnlo)
Find the dimensions of a rectangle whose area is 180 square meters and whose perimeter is (answered by palanisamy)
The length of a rectangle is 9 feet less than twice its width. The perimeter is 54 feet.... (answered by stanbon)
The length of a rectangle is 3 feet more than the width. The area of the rectangle is 54... (answered by checkley77)
a rectangle is 2x feet long and x+5 feet widw. the area is 600 square feet. what are the... (answered by scott8148)
A rectangle has perimeter 56 feet and it’s area is 180 sq feet find the dimensions of... (answered by MathLover1)
if the length of a rectangle is 3 feet greater than the width and it has an area of 28... (answered by JBarnum)
Find the dimensions of a rectangle whose perimeter is 24 feet and whose area is 35 square (answered by josgarithmetic)