SOLUTION: An area of 52 square feet is to be enclosed by two squares whose sides are in the ratio of 2:3. Find the sides of the two squares.

Algebra.Com
Question 229273: An area of 52 square feet is to be enclosed by two squares whose sides are in the ratio of 2:3. Find the sides of the two squares.
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
(2X)^2+(3X)^2=52
4X^2+9X^2=52
13X^2=52
X^2=52/13
X^2=4
X=2 ANS FOR THE SIDES OF THE SMALLER SQUARE.
PROOF:
(2*2)^2+(3*2)^2=52
4^2+6^2=52
16+35=52
52=52




RELATED QUESTIONS

An area of 52 square feet is to be enclosed by two squares whose sides are in the ratio... (answered by ankor@dixie-net.com)
Find the length of the sides of two squares whose areas are 448 square feet and 63 square (answered by mananth)
1. The combined area of two squares is 26 square meters. the sides of the larger square... (answered by stanbon)
A rectangular area is to be enclosed and then divided into thirds by two fences across... (answered by greenestamps)
a square tract of land has an area of 1600 square feet. it is enclosed on three sides by... (answered by mananth)
The combined area of two squares is 148 square meters. The sides of the larger square are (answered by mananth)
The combined area of two squares is 104 square meters. The sides of the larger square are (answered by sachi)
if two opposite sides of a square are each increased by 3 cm, and the other two sides are (answered by ankor@dixie-net.com)
In two square plots of grass, a side of one is ten yards longer than the side of the... (answered by josgarithmetic,MathTherapy,greenestamps)