# SOLUTION: The length of a rectangle is 8 in. more than its width. the perimeter of the rectangle is 24 in. what anr the width and length of the rectangle?

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 Click here to see ALL problems on Rectangles Question 229229: The length of a rectangle is 8 in. more than its width. the perimeter of the rectangle is 24 in. what anr the width and length of the rectangle?Found 2 solutions by drj, checkley77:Answer by drj(1380)   (Show Source): You can put this solution on YOUR website!The length of a rectangle is 8 in. more than its width. the perimeter of the rectangle is 24 in. what and the width and length of the rectangle? Step 1. Perimeter P means adding up all 4 sides of a rectangle. Step 2. Let w be the width. Step 3. Let w+8 be the length. Step 4. Then, P=w+w+w+8+w+8=24 since the perimeter is 24 inches Step 5. Solving P=w+w+w+8+w+8=24 yields the following steps Subtract 16 from both sides of the equation Divide by 4 to both sides of the equation and . Check Perimeter which is a true statement. Step 5. ANSWER: The width is 2 inches and the length is 10 inches. I hope the above steps were helpful. For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry. Good luck in your studies! Respectfully, Dr J Answer by checkley77(12569)   (Show Source): You can put this solution on YOUR website!L=W+8 2L+2W=24 2(W+8)+2W=24 2W+16+2W=24 4W=24-16 4W=8 W=8/4 W=2 ANS. FOR THE WIDTH. L=2+8=10 ANS. FOR THE LENGTH. PROOF: 2*10+2*2=24 20+4=24 24=24