SOLUTION: The length of a rectangle is 8 in. more than its width. the perimeter of the rectangle is 24 in. what anr the width and length of the rectangle?

Question 229229: The length of a rectangle is 8 in. more than its width. the perimeter of the rectangle is 24 in. what anr the width and length of the rectangle?
Found 2 solutions by drj, checkley77:
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 8 in. more than its width. the perimeter of the rectangle is 24 in. what and the width and length of the rectangle?

Step 1. Perimeter P means adding up all 4 sides of a rectangle.

Step 2. Let w be the width.

Step 3. Let w+8 be the length.

Step 4. Then, P=w+w+w+8+w+8=24 since the perimeter is 24 inches

Step 5. Solving P=w+w+w+8+w+8=24 yields the following steps

Subtract 16 from both sides of the equation

Divide by 4 to both sides of the equation

and . Check Perimeter which is a true statement.

Step 5. ANSWER: The width is 2 inches and the length is 10 inches.

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
L=W+8
2L+2W=24
2(W+8)+2W=24
2W+16+2W=24
4W=24-16
4W=8
W=8/4
W=2 ANS. FOR THE WIDTH.
L=2+8=10 ANS. FOR THE LENGTH.
PROOF:
2*10+2*2=24
20+4=24
24=24

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