SOLUTION: paul invested $6000 in two accounts. one pay 5% simple interest and other pays 3%. if the interestearned on the 3% investment is $60 more than the interest earned on the 5% investm
Algebra.Com
Question 224152: paul invested $6000 in two accounts. one pay 5% simple interest and other pays 3%. if the interestearned on the 3% investment is $60 more than the interest earned on the 5% investment, how much is investedat each rate?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.03x=.05(6,000-x)+60
.03x=300-.05x+60
.03x+.05x=360
.08x=360
x=360/.08
x=4,500 invested @ 3%.
6,000-4,500=1,500 invested @ 5%.
Proof:
.03*4,500=.05*1,500+60
135=75+60
135=135
RELATED QUESTIONS
I need help with this two equations six-step method problem.
Holly White invested... (answered by Alan3354)
Juanita has $24,000 to invest in two accounts that pay simple interest on an... (answered by lwsshak3)
I am still not able to figure this one out. Can someone show me step by step how to get... (answered by rothauserc)
Suppose $5,000 is divided into two bank accounts. One account pays 5% simple interest per (answered by stanbon)
Juanita has 28,000 to invest in two accounts that pay simple interest on an annual basis. (answered by richwmiller)
Paul wants to invest a total of $5000 in two accounts, one paying 4% annual simple... (answered by checkley71)
Juanita has 22000 to invest in two accounts that pay simple interest on an annual basis.... (answered by mananth)
Benjamin has $6000 invested in two accounts. One earns *5 interest per year, and the... (answered by stanbon)
If an investor invests a total of $25,000 into two bonds, one that pays 3% simple... (answered by Boreal)