SOLUTION: the perimeter of a rectangle is 140 m. The length is 4 m more than twice the width. Find the dimensions.

Question 223628: the perimeter of a rectangle is 140 m. The length is 4 m more than twice the width. Find the dimensions.
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangle is 140 m. The length is 4 m more than twice the width. Find the dimensions.

Step 1. Perimeter P means adding up all 4 sides of a rectangle.

Step 2. Let w be the width.

Step 3. Let 2w+4 be the length since it's 4 more than twice the width

Step 4. Then, P=w+w+2w+4+2w+4=6w+8=140

Solved by pluggable solver: EXPLAIN simplification of an expression

Your Result:

YOUR ANSWER

This is an equation! Solutions: w=22.
Graphical form: Equation was fully solved.
Text form: 6w+8=140 simplifies to 0=0
Cartoon (animation) form:
For tutors: simplify_cartoon( 6w+8=140 )
If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at .
Moved these terms to the left highlight_green%28+-140+%29

It becomes .

Look at .
Added fractions or integers together
It becomes .

Look at .
Removed extra sign in front of

It becomes .

Look at .
Solved linear equation highlight_red%28+6%2Aw-132=0+%29

equivalent to 6*w-132 =0
It becomes .
Result:
This is an equation! Solutions: w=22.

Universal Simplifier and Solver

Done!

With and . And which is a true statement

Step 5. ANSWER: The width is 22 meters and the length is 48 meters.

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J

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