SOLUTION: The perimeter of a rectangle is 42 inches. The lenth is twice the width. What are the dimensions? What is the area?

Question 218506: The perimeter of a rectangle is 42 inches. The lenth is twice the width. What are the dimensions? What is the area?
Found 2 solutions by checkley77, drj:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
L=2W
2L+2W=42
2*2W+2W=42
4W+2W=42
6W=42
W=42/6
W=7 IN. FOR THE WIDTH
L=2*7=14 IN. FOR THE LENGTH.
PROOF:
2*14+2*7=42
28+14=42
42=42

Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangle is 42 inches. The length is twice the width. What are the dimensions? What is the area?

Step 1. Perimeter P means adding up all the sides of a rectangle.

Step 2. Area A for a rectangle is length * width.

Step 3. Let w be the width

Step 4. Let 2w be the length since its twice the width.

Step 5. Then P=w+w+2w+2w=6w=42 or w=7 inches and 2w=14 inches.

Step 6. square inches

Step 7. ANSWER: The dimensions are 7 inches and 14 inches with an area of 98 square inches.

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J

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