# SOLUTION: The length of a rectangle is 4in longer than its width. If the perimeter of the rectangle is 28in, find its area.

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Question 217213: The length of a rectangle is 4in longer than its width. If the perimeter of the rectangle is 28in, find its area.
Found 2 solutions by rfer, ichudov:
Answer by rfer(12727)   (Show Source):
You can put this solution on YOUR website!
2x+2(x+4)=28
2x+2x+8=28
2x=20
x=5
x+4=9
----------
A=lw
A=9*5
A=45 sq in

Answer by ichudov(499)   (Show Source):
You can put this solution on YOUR website!
Keep in mind that perimeter is 2*length plus 2*width.

This is a linear system:

which you can solve with the linear solver
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
We'll use substitution. After moving -1*width to the right, we get:
, or . Substitute that
into another equation:
and simplify: Error: 'Can't call method "invoke_solver" on an undefined value at /home/ichudov/project_locations/algebra.com/templates/Algebra/Solver/PerlSolver.pm line 115. Can't call method "invoke_solver" on an undefined value at /home/ichudov/project_locations/algebra.com/templates/Algebra/Solver/PerlSolver.pm line 115. '. Can't call method "invoke_solver" on an undefined value at /home/ichudov/project_locations/algebra.com/templates/Algebra/Solver/PerlSolver.pm line 115. Can't call method "invoke_solver" on an undefined value at /home/ichudov/project_locations/algebra.com/templates/Algebra/Solver/PerlSolver.pm line 115.
error_location: 101