Question 217213: The length of a rectangle is 4in longer than its width. If the perimeter of the rectangle is 28in, find its area. Found 2 solutions by rfer, ichudov:Answer by rfer(16322) (Show Source): You can put this solution on YOUR website! 2x+2(x+4)=28
2x+2x+8=28
2x=20
x=5
x+4=9
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A=lw
A=9*5
A=45 sq in Answer by ichudov(507) (Show Source): You can put this solution on YOUR website! Keep in mind that perimeter is 2*length plus 2*width.
This is a linear system:
which you can solve with the linear solver
Solve: We'll use substitution. After moving -1*width to the right, we get: , or . Substitute that
into another equation: and simplify: So, we know that width=5. Since , length=9.