You can
put this solution on YOUR website!A rectangular parking lot has a length that is 3 yards greater than the width. The area of the parking lot is 180 yeards. What is the length and width of the parking lot.
Step 1. Let w be the width and w+3 is the length
Step 2. Let Area

or
where

where x=12 and x=-15.
Step 3. We can now also use the quadratic formula given as
where a=1, b=3 and c=-180.
Also, please ignore the graph since the scaling is not properly set.
| Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=729 is greater than zero. That means that there are two solutions: .


Quadratic expression can be factored:

Again, the answer is: 12, -15.
Here's your graph:
 |
Select x=12 for positive lengths. Then x+3=15
Step 4. ANSWER. The dimensions are 12 for the width and 15 for the length of the parking lot.
I hope the above steps were helpful.
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
And good luck in your studies!
Respectfully,
Dr J