SOLUTION: the perimeter of this rectangle is 74cm with length x+2 and with 3x. a.form an equation for the perimeter of the rectangle. b.solve your equation to find the length and with of t

Question 213908: the perimeter of this rectangle is 74cm with length x+2 and with 3x. a.form an equation for the perimeter of the rectangle. b.solve your equation to find the length and with of the rectangle
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
The perimeter of this rectangle is 74 cm with length x+2 and width 3x.

a. Form an equation for the perimeter of the rectangle.

b. Solve your equation to find the length and width of the rectangle.

Step 1. The perimeter of a rectangle P is when all the lengths of all 4 sides of a rectangle are added up.

Step 2. So . ANSWER to (a) is P=74=8x+4.

Step 3. Solving the equation for the perimeter yields the following steps:

Solved by pluggable solver: EXPLAIN simplification of an expression

Your Result:

YOUR ANSWER

This is an equation! Solutions: x=8.75.
Graphical form: Equation was fully solved.
Text form: 74=8x+4 simplifies to 0=0
Cartoon (animation) form:
For tutors: simplify_cartoon( 74=8x+4 )
If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at .
Moved these terms to the left highlight_green%28+-8%2Ax+%29

It becomes .

Look at .
Added fractions or integers together
It becomes .

Look at .
Moved

to the right of expression
It becomes .

Look at .
Solved linear equation highlight_red%28+-8%2Ax%2B70=0+%29

equivalent to -8*x+70 =0
It becomes .
Result:
This is an equation! Solutions: x=8.75.

Universal Simplifier and Solver

Done!

Step 4. ANSWER to b: With x= then length is l=8.75+2=10.75 cm and width is 3(8.75)=26.25 cm. Note perimeter is P=2(10.75+26.25)= 2*37=74 cm.

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J

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