SOLUTION: The perimeter of a rectangle is 56cm. The width is 6cm less than length. Find the width and length.

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangle is 56cm. The width is 6cm less than length. Find the width and length.      Log On


   



Question 212633This question is from textbook
: The perimeter of a rectangle is 56cm. The width is 6cm less than length. Find the width and length. This question is from textbook

Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangle is 56cm. The width is 6cm less than length. Find the width and length.

Step 1. Let l = w+6 length of rectangle and let w be the width

Step 2. Let P = 56 cm be the perimeter. Perimeter means adding the 4 sides of a rectangle. So,

P=w%2B6%2Bw%2B6%2Bw%2Bw

P=4w%2B12

P=4w%2B12=56

Step 3. Subtract 12 to both sides of equation to get 4w by itself


P=4w%2B12-12=56-12

4w=44

Step 4. Divide 4 to both sides of equation

4w%2F4=44%2F4

w=+11+

Step 5. w = 11 cm is the width of the rectangle and length is 17 cm since

l=w+6=17

Check P=4w+12=4(11)+16=44+12=56 So w = 11 cm and l = 17 cm is the solution.

Hope the above steps were helpful. Good luck in your homework and studies!

Respectfully
Dr J

Hope you understood and followed the steps. Good luck in your studies. Dr J

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra