# SOLUTION: The length of a rectangular garden is 8 feet longer than its width. If the garden's perimeter is 180 feet, what is the area of the garden in square feet?

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 Click here to see ALL problems on Rectangles Question 212246: The length of a rectangular garden is 8 feet longer than its width. If the garden's perimeter is 180 feet, what is the area of the garden in square feet? Found 2 solutions by rfer, drj:Answer by rfer(12657)   (Show Source): You can put this solution on YOUR website!2(x+8)+2x=180 2x+16+2x=180 4x=164 x=41 x+8=49 --------------- a=lw a=49*41 a=2009 sq ft Answer by drj(1380)   (Show Source): You can put this solution on YOUR website!The length of a rectangular garden is 8 feet longer than its width. If the garden's perimeter is 180 feet, what is the area of the garden in square feet? Step 1. Let w be the width of the rectangular garden. Step 2. Let w+8 be the length of the rectangular garden. Step 3. Let P be the perimeter of the rectangular garden. Step 4. P=2(w+w+8) since we have 2w plus 2(w+8) be lengths of the 4 sides. A rectangular perimeter is adding the four lengths of the sides of a rectangle. Divide by four on both sides of equation to yield Step 5. Area is length times width for a rectangle. Substituting w=41 and w+8=49 into A yields ANSWER: Area A=2009 Hope this helps and good luck in the future! Dr J For Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra