SOLUTION: The length of a rectangular garden is 8 feet longer than its width. If the garden's perimeter is 180 feet, what is the area of the garden in square feet?

Question 212246: The length of a rectangular garden is 8 feet longer than its width. If the garden's perimeter is 180 feet, what is the area of the garden in square feet?

Found 2 solutions by rfer, drj:
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
2(x+8)+2x=180
2x+16+2x=180
4x=164
x=41
x+8=49
---------------
a=lw
a=49*41
a=2009 sq ft
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
The length of a rectangular garden is 8 feet longer than its width. If the garden's perimeter is 180 feet, what is the area of the garden in square feet?

Step 1. Let w be the width of the rectangular garden.

Step 2. Let w+8 be the length of the rectangular garden.

Step 3. Let P be the perimeter of the rectangular garden.

Step 4. P=2(w+w+8) since we have 2w plus 2(w+8) be lengths of the 4 sides. A rectangular perimeter is adding the four lengths of the sides of a rectangle.

Divide by four on both sides of equation to yield

Step 5. Area is length times width for a rectangle.

Substituting w=41 and w+8=49 into A yields

ANSWER: Area A=2009

Hope this helps and good luck in the future! Dr J

For Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra

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