SOLUTION: a few questions that i need to check my work on The length (L) of a rectangle is 2 feet less than 10 times its width (W). If the perimeter of the rectangle is 62 feet, find the

Question 211034: a few questions that i need to check my work on
The length (L) of a rectangle is 2 feet less than 10 times its width (W). If the perimeter of the rectangle is 62 feet, find the rectangle's dimensions.

The perimeter of a rectangle is 78 inches. If the length of the rectangle is seven inches more than three times the width, find the dimensions.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
L=10W-2
2L+2W=62
2(10W-2)+2W=62
20W-4+2W=62
22W=62+4
22W=66
W=66/22
W=3 FT.
L=10*3-2
L=30-2
L=28 FT.
PROOF:
2*28+2*3=62
56+6=62
62=62
-------------------------------------
2(3W+7)+2W=78
6W+14+2W=78
8W=78-14
8W=64
W=64/8
W=8 IN.
L=3*8+7
L=24+7
L=31 IN.
PROOF:
2*31+2*8=78
62+16=78
78=78

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