SOLUTION: the length of a rectangle is 8 in. more than its width. The perimiter of the rectangle is 24 in. what are the length and width of the rectangle?

Question 209252This question is from textbook ALEBRA 1
: the length of a rectangle is 8 in. more than its width. The perimiter of the rectangle is 24 in. what are the length and width of the rectangle? This question is from textbook ALEBRA 1

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
the length of a rectangle is 8 in. more than its width. The perimiter of the rectangle is 24 in. what are the length and width of the rectangle?
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Let width be W
Then length = W+8 inches
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Perimeter = 2(W + L)
24 = 2(W + W+8)
12 = 2W+8
2W = 4
W = 2 inches (Width)
L = W+8 = 10 inches (Length)
================================
Cheers,
Stan H.
Reply to stanbon@comcast.net
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