SOLUTION: The length of a rectangle is 6 cm more than 1 1/2 times the width. The perimiter of the rectangle is 56 cm. Find the dimensions of the rectangle.Can someone show me the work too?

Question 206510: The length of a rectangle is 6 cm more than 1 1/2 times the width. The perimiter of the rectangle is 56 cm. Find the dimensions of the rectangle.Can someone show me the work too?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 6 cm more than 1 1/2 times the width. The perimiter of the rectangle is 56 cm. Find the dimensions of the rectangle
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Perimeter = 2(W + L)
56 = 2(W + (3/2)W + 6)
28 = (5/2)W + 6
(5/2)W = 22
W = 44/5 = 8.8 cm
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L = (3/2)W + 6
L = (3/2)*8.8 + 6
L = 19.2 cm
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Cheers,
Stan H.
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