SOLUTION: The length of a rectangle is 6 cm more than 1 1/2 times the width. The perimiter of the rectangle is 56 cm. Find the dimensions of the rectangle.Can someone show me the work too?
Algebra.Com
Question 206503: The length of a rectangle is 6 cm more than 1 1/2 times the width. The perimiter of the rectangle is 56 cm. Find the dimensions of the rectangle.Can someone show me the work too?
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
width=x=8.8
length=1.5x+6=19.2
---------------
P=2L+2W
2(1.5x+6)+2x=56
3x+12+2x=56
subtract 12 from both sides.
5x=56-12
5x=44
x=8.8
--------------
P=2(8.8)+2(19.2)=56
RELATED QUESTIONS
The length of a rectangle is 6 cm more than 1 1/2 times the width. The perimiter of the... (answered by )
The length of a rectangle is 6 cm more than 1 1/2 times the width. The perimiter of the... (answered by stanbon)
the area of a rectangle has an area of 52cm^2 and its length is 1 cm more than 3 times... (answered by dbashant)
The length of a rectangle is 1 cm more than the width. If the perimeter of the rectangle... (answered by jake_6233)
the perimater of a rectangle is 56 cm. the lenth of the rectangle is 2 cm more than the... (answered by blubunny01)
The perimeter of a rectangle is 62 cm. The length of the rectangle is 1 cm more than... (answered by ewatrrr)
Please help me solve.
The length of a rectangle is 1 cm more than 2 times its width.... (answered by scott8148)
The length of a rectangle is 1 cm more than 4 times its width. If the area of the... (answered by checkley71)
The length of a rectangle is 1 cm more than 4 times its width. If the area of the... (answered by ptaylor)