SOLUTION: The length of a rectangle is 3yd more than twice its width, and the area of the rectangle is 77yd^2 . Find the dimensions of the rectangle
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Question 205093: The length of a rectangle is 3yd more than twice its width, and the area of the rectangle is 77yd^2 . Find the dimensions of the rectangle
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
L=2W+3
L*W=AREA
(2W+3)W=77
2W^2+3W=77
2W^2+3W-77=0
(2W-11)(W+7)=0
2W-11=0
2W=11
W=11/2
W=5.5 ANS. FOR THE WIDTH.
L=2*5.5+3
L=11+3
L=14 ANS. FOR THE LENGTH.
PROOF:
5.5*14=77
77=77
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