SOLUTION: The length of a rectangle is 3 more than twice its width. The perimeter is 48 feet. Find the width.
Algebra.Com
Question 204769: The length of a rectangle is 3 more than twice its width. The perimeter is 48 feet. Find the width.
Answer by lazi(15) (Show Source): You can put this solution on YOUR website!
L = 2W + 3
P = 48
P = 2(W + L)
48 = 2(w + 2W + 3)
48 = 2(3W + 3)
48 = 2 * 3(W + 1)
48 = 6(W + 1)
8 = W + 1
7 = W
RELATED QUESTIONS
The length of a rectangle is 3 more than twice its width. The perimeter is 48 feet. Find... (answered by alicealc)
The length of a rectangle is 3 meters more than twice its width. The perimeter of the... (answered by swincher4391)
The length of a rectangle is 2 feet more than twice its width. If its perimeter is 28... (answered by PRMath)
The length of a rectangle is 3 feet less than twice its width and the perimeter is 72... (answered by stanbon)
The width of a rectangle is 3 feet more than twice the length. If the perimeter is 60... (answered by checkley79)
The length of a rectangle is 3 meters more than twice its width. The perimeter is 48... (answered by Adrianne15)
the length of a rectangle is 5 more than twice it's width. its perimeter is 88 feet.... (answered by Alan3354)
The length of a rectangle is 5 feet more than twice its width. Find the dimensions of the (answered by algebrahouse.com)
The length of a rectangle is 3 m more than twice its width. If the perimeter of the... (answered by TimothyLamb)