SOLUTION: The sides of a rectangle are x and x+6. The area of the rectangle is 55. Find the lenghts of the sides.(an algebraic solution will be accepted.)

Algebra.Com
Question 196664: The sides of a rectangle are x and x+6. The area of the rectangle is 55. Find the lenghts of the sides.(an algebraic solution will be accepted.)
Answer by vleith(2983)   (Show Source): You can put this solution on YOUR website!





x = -11 or 5
Since a side cannot be negative, x = 5
Then x+6 = 11

RELATED QUESTIONS

THE AREA OF A RECTANGLE IS 105 METERS SQUARE. THE LENGTH IS ONE MORE THAN TWICE THE... (answered by solver91311)
Find an algebraic expression for the quantity in italics using the given information.... (answered by rapaljer)
A rectangle is such that the lenghts of two of its adjacent sides differ by 5cm. A... (answered by KMST)
The area of a rectangular field is 450m^2 and the difference between the lenghts of the... (answered by ikleyn)
the sides of a rectangle are (x+2) and (x+3) and the diagonal is (x+5) , find... (answered by Alan3354)
what are the possible lenghts and widths that would give a rectangle an area of 48 square (answered by solver91311)
the sides of a rectangle B are 20% greater than the sides of rectangle A. rectangle B's... (answered by josgarithmetic)
The lenghts of the sides of a triangle are x, 2x+2, and 13. If the perimeter of the... (answered by hinaahsan)
the sides of a rectangle are all exactly equal and its area is 144. how long are the... (answered by ewatrrr)