SOLUTION: The length of a rectangle is 3 feet longer than the width. The permineter is 30 feet. Find the dimensions of the rectangle.
a. length = 8 feet; width = 5 feet
b. length = 8 feet;
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Question 190102This question is from textbook Beginning & Intermediate Algebra
: The length of a rectangle is 3 feet longer than the width. The permineter is 30 feet. Find the dimensions of the rectangle.
a. length = 8 feet; width = 5 feet
b. length = 8 feet; width = 7 feet
c. length = 9 feet; width = 6 feet
This question is from textbook Beginning & Intermediate Algebra
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
P=2L+2w
.
L=w+3
2(w+3)+2w=30 Substitute w+3 for L
2w+6+2w=30
4w=24
w=6
L=9
.
Ed
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