SOLUTION: The length of a rectangle is 3 feet more than twice its width, and 2 feet less than a diagonal's length. Find the length of the diagonal in simplest radical form.

Question 183956: The length of a rectangle is 3 feet more than twice its width, and 2 feet less than a diagonal's length. Find the length of the diagonal in simplest radical form.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 3 feet more than twice its width, and 2 feet less than a diagonal's length. Find the length of the diagonal in simplest radical form.
---------------
Let width = W.
Then Length = "2W+3"
---------------------------
Equation:
diagonal^2 = leg^2 + leg^2
d^2 = x^2 + (2x+3)^2
d^2 = x^2 + 4x^2 + 12x + 9
d^2 = 5x^2 + 12x + 9
-----
d = sqrt(5x^2+12x+9)
===========================
Cheers,
Stan H.

RELATED QUESTIONS
The length of a rectangle is 3 feet less than twice its width and the perimeter is 72... (answered by stanbon)

The length of a rectangle is 2 feet more than twice its width. If its perimeter is 28... (answered by PRMath)

The length of a rectangle 3 feet more than three times its width. The diagonal of the... (answered by jorel1380)

The length of a rectangle is 2 feet less than twice its width. If the perimeter is 26... (answered by Cromlix)

If the length of a rectangle is 3 feet longer than its width and the diagonal is (answered by solver91311)

The length of a rectangle is 3 more than twice its width. The perimeter is 48 feet. Find... (answered by lazi)

The length of a rectangle is 3 more than twice its width. The perimeter is 48 feet. Find... (answered by alicealc)

The perimeter of a rectangle is 80 feet, and it's length is 5 feet less than twice its... (answered by algebrahouse.com)

The width of a rectangle is 3 feet more than twice the length. If the perimeter is 60... (answered by checkley79)