SOLUTION: The area of a rectangle is 48 square centimeters. If the width is 1/3 of the lenght, find the dimensions of the rectangle.
Algebra.Com
Question 171299: The area of a rectangle is 48 square centimeters. If the width is 1/3 of the lenght, find the dimensions of the rectangle.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
xy=48
x=y/3
y/3*y=48
y^2/3=48
y^2=3*48
y^2=144
y=sqrt144
y=12 ans.
x=12/3
x=4 ans.
Proof:
4*12=48
48=48
RELATED QUESTIONS
Suppose that the lenght of a rectangle is one and one-third times long as its width. The (answered by brandonpark2889)
the length of a rectangle is 3 more than the width. If the area of the rectangle is 10... (answered by greenestamps,solver91311)
1) The lenght of a rectangle is 4 meters less than twice the width. If the area of the... (answered by ewatrrr)
the width of a rectangle is 15 cm less than 3 times the lenght if the area is 42 square... (answered by josgarithmetic)
the width of a rectangle is 15 cm less than 3 times the lenght if the area is 42 square... (answered by ikleyn)
Please help, I am lost at how to do this problem.
The combined area of a square and a... (answered by scott8148)
the area of a rectangle is 54 square centimeters. the length of the rectangle is 1*1/2... (answered by Alan3354)
The area of a rectangle is 48 square centimeters. If the length of the rectangle is 8... (answered by RAY100)
The area of a rectangle is 48 square centimeters. If the length of the rectangle is 8... (answered by CharlesG2)